# How do you solve the following linear system: 3x + 5y = -1, 3x+y=-2?

Nov 14, 2015

$\left(x , y\right) = \left(- \frac{3}{4} , \frac{1}{4}\right)$

#### Explanation:

Given:
[1]$\textcolor{w h i t e}{\text{XXX}} 3 x + 5 y = - 1$
[2]$\textcolor{w h i t e}{\text{XXX}} 3 x + y = - 2$

Subtract [2] from [1]
[3]$\textcolor{w h i t e}{\text{XXX}} 4 y = 1$
Divide [3] by 4
[4]$\textcolor{w h i t e}{\text{XXX}} y = \frac{1}{4}$

Substitute $\frac{1}{4}$ for $y$ in [2]
[5]color(white)("XXX")3x+1/4 =-2 Subtract 1/4 from both sides of [5] [6]color(white)("XXX")3x = -9/4 Divide [6] by 3 [7]color(white)("XXX")x = -3/4#