# How do you solve the following linear system:  3y-15=x , x-4y=-19 ?

$\left(- 3 , 4\right)$

#### Explanation:

We can substitute the first equation, $3 y - 15 = x$, into the second equation, $x - 4 y = - 19$:

$\left(3 y - 15\right) - 4 y = - 19$

$- y - 15 = - 19$

-y=-4=>color(blue)(bar(ul(abs(color(black)(y=4))))

$3 y - 15 = x$

$3 \left(4\right) - 15 = x$

12-15=x=>color(blue)(bar(ul(abs(color(black)(x=-3

And we can see that when we graph the two lines:

graph{(3y-x-15)(x-4y+19)=0[-10,10,0,10]}