# How do you solve the following linear system:  x - 3y = -3, x + 3y = 9, ?

$x = 3$
$y = 2$

#### Explanation:

The given equations are
$x - 3 y = - 3 \text{ }$first equation
$\underline{x + 3 y = 9 \text{ }}$second equation
$2 x + 0 = 6$$\leftarrow$the result after adding the terms

and $2 x = 6$

$x = 3$

We can now solve for $y$ using $x = 3$ and second equation

$x + 3 y = 9 \text{ }$second equation
$3 + 3 y = 9 \text{ }$second equation
$3 y = 9 - 3$
$3 y = 6$

$y = 2$

God bless....I hope the explanation is useful.