How do you solve the following linear system x-3y= 9, 7x+2y=-3 ?

May 25, 2018

$x = - \frac{66}{23} , y = \frac{405}{23}$
Multiplying the first equation by$- 7$ and adding to the second we get
$23 y = - 66$ so
$y = - \frac{66}{23}$
$x = 9 + 3 \cdot \frac{66}{23} = \frac{9 \cdot 23 + 3 \cdot 66}{23} = \frac{405}{23}$