How do you solve the following linear system: #x - 5y = 3, y= 3x + 2 #?
1 Answer
Nov 16, 2015
x-5y=3⇨equation 1
y=3x+2⇨change x as the tittle
-3x+y=2⇨equation 2
x-5y=3⇨equation 1
-3x+y=2⇨equation 2
(Equation 1×3)
3x-15y=3→equation 3
-3x+y=2⇨equation 2
Equation 3 + equation 2
-14y=5
y=-5/14
Substitute value of y into x:
-3x-5/14=2
-42x-5=28
-42x=33
x=-33/42
