#y=-3x+8..............(i)# #y=2x+3................(ii)#
Since the #L.H.S# of #(i)# and #(ii)# are equal to the same variable #y# therefore the #R.H.S# of #(i)# and #(ii)# will also be equal. #implies 2x+3=-3x+8# #implies 5x=5# #implies x=1#
Put #x=1# in #(ii)# #implies y=2*1+3# #implies y=5#