How do you solve the following system?: # 1/2x=y-1 , -x+3y=-7 # Algebra Systems of Equations and Inequalities Systems Using Substitution 1 Answer chinni · Stefan V. Apr 24, 2018 Answer: #x=-20# #y=-9# Explanation: The given equations are # 1/2x = y-1# # -x+3y = -7# From #1/2x = y-1# # x=2(y-1)# Substituting this #x# value in equation #-x+3y = -7# #=> - (2(y-1) + 3y = -7# #=> -2y +2 +3y = -7# #=> y+2 = -7# #=> y= -7-2# #=> y = -9# Substitute this #y# value in any of the given equations to obtain the #x# value #-x +3y = -7# #=> -x + 3(-9) = -7# #=> -x -27 = -7# #=> x = -20 # Related questions How do you solve systems of equations using the substitution method? How do you check your solutions to a systems of equations using the substitution method? When is the substitution method easier to use? How do you know if a solution is "no solution" or "infinite" when using the substitution method? How do you solve #y=-6x-3# and #y=3# using the substitution method? How do you solve #12y-3x=-1# and #x-4y=1# using the substitution method? Which method do you use to solve the system of equations #y=1/4x-14# and #y=19/8x+7#? What are the 2 numbers if the sum is 70 and they differ by 11? How do you solve #x+y=5# and #3x+y=15# using the substitution method? What is the point of intersection of the lines #x+2y=4# and #-x-3y=-7#? See all questions in Systems Using Substitution Impact of this question 176 views around the world You can reuse this answer Creative Commons License