How do you solve the following system: #11y + 3x = 4, -6y - 2x = 0 -3 #?

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Answer 1 · 2016-07-25T18:27:35

The Soln. #x=9/4, y=-1/4#.

#11y+3x=4................(1)#

#-6y-2x=-3...........(2)#.

Multiplying #(1)# by #2#, we get, #22y+6x=8... ... (1star)#

Multiplying #(2)# by #3#, we get, #-18y-6x=-9... ...(2star)#

Adding #(1star) and (2star)#, we get,

#22ycancel(+6x)-18ycancel(-6x)=8-9#

#:. 4y=-1 rArr y=-1/4#.

Sub.ing #y=-1/4# in #(2)#, we get,

#-6(-1/4)-2x=-3, i.e., -2x=-3-3/2=-9/2#

#:. x=9/4#.

Hence, the Soln. #x=9/4, y=-1/4#.