How do you solve the following system?: $11y=5x- 6 , 2y=7x-3$

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Answer 1 · 2016-02-11T15:45:28

$x=21/67$ and $y=-27/67$

from the given equations

$11y=5x-6$ and $2y=7x-3$ rearrange the terms so that they become as follows

$5x-11y=6$ the 1st equation
$7x-2y=3$ the 2nd equation

Elimination by subtraction. Multiply the 2nd equation by $11$
and multiply the 1st equation by $2$ so that they become

$10x-22y=12$ the 1st equation
$77x-22y=33$ the 2nd equation

perform subtraction

$67x+0=21$

and $67x=21$

$x=21/67$

from the original 2nd equation, use $x=21/67$

$2y=7x-3$
$2y=7(21/67)-3$

$2y=147/67-201/67$

$y=1/2((147-201)/67)$

$y=1/2((-54)/67)$

$y=-27/67$

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How do you solve the following system?: 11y=5x- 6 , 2y=7x-3 11y=5x- 6 , 2y=7x-3