How do you solve the following system?: #-12x -15y =3, 13x -16y = -4#

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Answer 1 · 2017-07-24T11:26:49

After some arrangement, #x=-12# and #y=1/43#

Enlarge the first equation with 13 and the second equation with 12:

#-156x - 195y = 39#
#156x - 192y = -48#

Combine these two equations:

#-387y = -9#

#y= 9/387#

#y=1/43#

Now you can calculate x (for example using the second original equation):

#13x - 16/43 = -4#

#13x = -4 + 16/43#

#13x = -156#

#x= -156/13#

#x= -12#