How do you solve the following system?: $12x +33y =1, -4x +5y = -2$

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Answer 1 · 2018-04-16T10:40:01

By arranging the equation

$12x + 33y = 1$
$-12x + 15y = -6$

(after multiplying 3)

Now add the two equations:

$48y = -5$

$y=-5/48$

Put this value in the 1st original equation:

$12x = 1-(33times-5/48)$

$12x = 1+(165/48)$

$12x = (48+165)/48$

$12x = 213/48$

$12x = 71/16$

$x = 71/(16times12)$

$x=71/192$

Your solution:

$x=71/192$
$y=-5/48$

or

$y=-20/192$

How do you solve the following system?: 12x +33y =1, -4x +5y = -212x +33y =1, -4x +5y = -2