How do you solve the following system?: 16x +3y =7, 9x +5y = -12

1 Answer
Jan 4, 2016

(x,y)=(71/53, -255/53)

Explanation:

Given
[1]color(white)("XXX")16x+3y=7
[2]color(white)("XXX")9x+5y=-12

Multiply [1] by 5 and [2] by 3 to get equations with equal coefficients for y
[3]color(white)("XXX")80x+15y=35
[4]color(white)("XXX")27x+15y=-36

Subtract [4] from [3]
[5]color(white)("XXX")53x=71

Divide by 23
[6]color(white)("XXX")x=71/53
color(white)("XXX")Yes; it's going to be ugly; but that doesn't mean it's going to be wrong.

Substitute 71/53 for x in [1]
[7]color(white)("XXX")(16xx71)/53+3y=7

Simplify
[8]color(white)("XXX")1136/53+159/53y=371/53

[9]color(white)("XXX")159y=-765

[10]color(white)("XXX")y=-765/159=-255/23

I would (strongly) recommend using a calculator or spreadsheet to verify these values in the original equations.