How do you solve the following system?: $-2x+10y=-20 , 2x+3y=11$

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Answer 1 · 2016-01-21T09:15:27

${ (x=(85)/13),(y=-9/13) :}$

${ (-2x+10y=-20" S1"),(2x+3y=11" S2") :}$

You can use Linear Systems with Addition or Subtraction doing $S1+S2$ to remove $x$ (in the equations $x$ has same coefficent and opposite sign).

You also could divide the first equation $S1$ by $2$

${ (-cancel(2)x+cancel(10)^5y=-cancel(20)^10" S1/2"),(0x+13y=-9 " S1+S2") :}$

$=>{ (-x+5y=-10),(y=-9/13) :}$

${ (-x=-10-5*(-9/13)),(y=-9/13) :}$

${ (x=10-45/13),(y=-9/13) :}$

${ (x=(130-45)/13),(y=-9/13) :} =>{ (x=(85)/13),(y=-9/13) :}$

graph{(10y-2x+20)(3y+2x-11)=0 [3.734, 8.059, -1.165, 0.998]}

How do you solve the following system?: -2x+10y=-20 , 2x+3y=11 -2x+10y=-20 , 2x+3y=11