How do you solve the following system?: $-2x+12y=-20 , x-5y=15$

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Answer 1 · 2016-04-19T05:41:18

The solution for the system of equations is:
$color(green)(x=40$
$color(green)(y= 5$

$color(green)(- 2x) + 12 y = -20$ ..........equation $(1)$

$x - 5y = 15$ , multiplying by $2$
$color(green)(2x) - 10y = 30$ ....................equation $(2)$

Solving by elimination.

Adding equations $1$ and $2$ eliminates $2x$

$cancel color(green)(- 2x) + 12 y = -20$
$cancelcolor(green)(2x) - 10y = 30$

$2y = 10$

$y = 10/2$

$color(green)(y= 5$

Finding $x$ from the second equation provided:

$color(blue)(x) - 5y = 15$

$x = 15+ 5y$

$x = 15+ 5 * color(green)(5$

$x = 15+ 25$

$color(green)(x=40$

How do you solve the following system?: -2x+12y=-20 , x-5y=15 -2x+12y=-20 , x-5y=15