# How do you solve the following system?:  2x + 3y = 1 , 3x − y = 30

Aug 2, 2017

Arrange equations. $x = \frac{91}{11}$ and $y = - \frac{57}{11}$

#### Explanation:

Second equation will be rewritten:
$9 x - 3 y = 90$
$2 x + 3 y = 1$ (the first equation)

$11 x = 91$
$x = \frac{91}{11}$

Now you can get y
$2 \times \left(\frac{91}{11}\right) + 3 y = 1$

$3 y = 1 - \frac{182}{11}$

$3 y = - \frac{171}{11}$

$y = - \frac{171}{33}$

or $y = - \frac{57}{11}$