How do you solve the following system?: # 2x + 3y = 1 , 3x − y = 30 #

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Answer 1 · 2017-08-02T08:26:08

Arrange equations. #x=91/11# and #y=-57/11#

Second equation will be rewritten:
#9x - 3y = 90#
#2x + 3y= 1# (the first equation)

Add these:
#11x = 91#
#x=91/11#

Now you can get y
#2times(91/11) + 3y = 1#

#3y = 1 - 182/11#

#3y= -171/11#

#y= -171/33#

or #y=-57/11#