How do you solve the following system?: #-2x -3y =-3, 4x -5y = -4#

1 Answer
Jun 8, 2018

Answer:

#x=3/22, y=10/11#

Explanation:

You have the system:
1) #-2x-3y=-3#
2) #4x-5y=-4#

Multiply 1) with 2 and add the resulting equation to 2), like this:
#-4x-6y=-6#
#4x-5y=-4#
Adding these together term by term, we get:
#-11y=-10#

#=>y=10/11#
From 1) we get:
#2x=-3y+3=-30/11+3=3/11#
#x=3/22#

It is always a good idea to use the results found and put them into the original system:

1) #-2x-3y=-2*3/22-3*10/11=-(6+60)/22=-3# Check
2) #4x-5y=4*3/22-5*10/11=(6-50)/11=-4# Check