How do you solve the following system?: #2x +3y =5 , 8x +5y = -4#

1 Answer
Apr 21, 2018

Answer:

#X = 33/16 and Y = 48/14#

Explanation:

Given:
#2x+3y = 5 and 8x + 5y = -4#
We need to make either one of the terms given, have similar coefficients to cancel out.

#(2x + 3y = 5)# x #8#
#color(red)(16x + 24y = 40)#

#(8x+ 5y = -4)# x #2#
#color(red)(16x + 10y = -8)#

Subtracting one from the other, we get:
#16x + 24 y = 40#
#-(16x+10y = -8)#

We get #14y = 48; y =48/14#

Substituting y = #48/14# in any one of the equations.
#2x + cancel(3)(14/cancel(48)) = 5#
#2x + 7/8 = 5#
#2x = 5-7/8#
#2x = (40-7)/8#
#:. x = 33/16#