How do you solve the following system: $2 x - 5 y = - 19, 3 x + 2 y = 0$ $2x-5y=-19, 3x+2y =0$ ?

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How do you solve the following system: $2 x - 5 y = - 19, 3 x + 2 y = 0$ $2x-5y=-19, 3x+2y =0$ ?

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Answer 1 · 2015-12-09T21:24:37

$x = - 2, y = 3$ $x=-2, y=3$

Explanation:

$2 x - 5 y = - 19, 3 x + 2 y = 0$ $2x-5y=-19, 3x+2y=0$

$3 x + 2 y = 0$ $3x+2y=0$
$3 x = - 2 y + 0$ $3x=-2y+0$
$x = - \frac{2}{3} y$ $x=-2/3y$

Plug in $x$ $x$ for $2 x - 5 y = - 19$ $2x-5y=-19$

$2 (- \frac{2}{3} y) - 5 y = - 19$ $2(-2/3y)-5y=-19$
$- \frac{4}{3} y - 5 y = - 19$ $-4/3y-5y=-19$
$- \frac{4}{3} y - \frac{15}{3} y = - 19$ $-4/3y-15/3y=-19$
$- \frac{19}{3} y = - 19$ $-19/3y=-19$
$3 (- \frac{19}{3} y) = 3 (- 19)$ $3(-19/3y)=3(-19)$
$- 19 y = - 57$ $-19y=-57$
$y = 3$ $y=3$

Plug in $y$ $y$ in $x = - \frac{2}{3} y$ $x=-2/3y$ to get $x$ $x$

$x = - \frac{2}{3} (3)$ $x=-2/3(3)$
$x = - 2$ $x=-2$

$x = - 2, y = 3$ $x=-2, y=3$

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How do you solve the following system: $2 x - 5 y = - 19, 3 x + 2 y = 0$ $2x-5y=-19, 3x+2y =0$ ?

1 Answer

Explanation:

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How do you solve the following system: 2x-5y=-19, 3x+2y =0 2x−5y=−19,3x+2y=02x-5y=-19, 3x+2y =0 ?

1 Answer

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How do you solve the following system: $2 x - 5 y = - 19, 3 x + 2 y = 0$ $2x-5y=-19, 3x+2y =0$ ?