# How do you solve the following system: #-2x + 5y = 20, x +4y = 16#?

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Rachel
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Mar 21, 2018

Let's use substitution:

*We need to solve for #x# in the second equation*

*Now we substitute #(16 - 4y)# for #x# in the first equation*

*distribute the #-2#*

*Solve for #y#. Add #32# to both sides*

*Divide by #13# on both sides*

We have

To check our work, let's plug our values for

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