How do you solve the following system?: $- 2 x + 5 y = - 6, 3 x + 2 y = - 1$ $-2x +5y =-6 , 3x +2y = -1$

Question

How do you solve the following system?: $- 2 x + 5 y = - 6, 3 x + 2 y = - 1$ $-2x +5y =-6 , 3x +2y = -1$

1 Answer

Impact of this question

1442 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2016-08-15T10:04:51

$x = \frac{7}{19} and y = - \frac{20}{19}$ $x = 7/19 and y = -20/19$

Explanation:

As the x-terms have different signs, we will eliminate them by using an LCM of 6 and adding.

$- 2 x + 5 y = - 6$ $-2x +5y =-6$ .............................................. A

$3 x + 2 y = - 1$ $3x +2y = -1$ ....................................................B

Ax3: $- 6 x + 15 y = - 18$ $-6x+15y = -18$ .......... ......................................C

Bx2: $6 x + 4 y = - 2$ $" "6x+4y=-2$ ........................................................D

C+D: $19 y = - 20$ $" " 19y= -20$

$y = \frac{- 20}{19}$ $y = (-20)/19$

Substitute $\frac{- 20}{19}$ $(-20)/19$ for y in B

$3 x + 2 (\frac{- 20}{19}) = - 1 \times 19$ $3x + 2((-20)/19) = -1 " "xx19$

$19 \times 3 x + \frac{- 40}{19} \times 19 = - 1 \times 19$ $19xx3x + (-40)/19xx19 = -1xx19$

$57 x - 40 = - 19$ $57x-40 = -19$

$57 x = 21$ $57x = 21$

$x = \frac{21}{57} = \frac{7}{19}$ $x = 21/57 = 7/19$

Check in A

$\frac{- 2 \times 7}{19} + \frac{5 \times (- 20)}{19}$ $(-2xx7)/19 +(5xx(-20))/19$

$\frac{- 14 - 100}{19}$ $(-14-100)/19$

$- \frac{114}{19}$ $-114/19$

= $- 6$ $-6$

Science

Math

Humanities

... and beyond

How do you solve the following system?: $- 2 x + 5 y = - 6, 3 x + 2 y = - 1$ $-2x +5y =-6 , 3x +2y = -1$

1 Answer

Explanation:

Related questions

Impact of this question

Science

Math

Humanities

... and beyond

How do you solve the following system?: -2x +5y =-6 , 3x +2y = -1−2x+5y=−6,3x+2y=−1 -2x +5y =-6 , 3x +2y = -1

1 Answer

Explanation:

Related questions

Impact of this question

How do you solve the following system?: $- 2 x + 5 y = - 6, 3 x + 2 y = - 1$ $-2x +5y =-6 , 3x +2y = -1$