How do you solve the following system?: $- 2 x + y = 1, - x + y = - 3$ $-2x+y=1, -x+y=-3$

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Answer 1 · 2015-12-23T17:01:40

The solution for the system of equations is
$x = - 4, y = - 7$ $color(blue)(x=-4,y=-7$

$- 2 x + y = 1$ $-2x+color(blue)(y)=1$ ......equation $(1)$ $(1)$

$- x + y = - 3$ $-x+color(blue)(y)=-3$ ....equation $(2)$ $(2)$

Solving by **elimination **

Subtracting equation $2$ $2$ from $1$ $1$

$-2x+cancelcolor(blue)(y)=1$

$+x-cancelcolor(blue)(y)=+3$

$-x=4$

$color(blue)(x=-4$

Finding $y$ by substituting $x$ in equation $1$ :
$-2x+y=1$

$-2 xx (-4)+y=1$

$8+y=1$

$y=1-8$

$color(blue)(y=-7$

How do you solve the following system?: -2x+y=1, -x+y=-3 −2x+y=1,−x+y=−3-2x+y=1, -x+y=-3