How do you solve the following system?: #2x +y =7, 8x -7y = 0#

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Answer 1 · 2016-09-03T10:28:19

#x=49/22#

#y=28/11#

#2x+y=7# or #8x+4y=28#

#8x-7y=0#

or

#8x=7y#

Plugging the value #8x=7y# in the equation

#8x+4y=28#

We get

#7y+4y=28#

or

#11y=28#

or

#y=28/11#------------------------------Ans #1#

Plugging the value #y=28/11# in the equation #2x+y=7#

We get

#2x+28/11=7#

or

#2x=7-28/11#

or

#x=49/11times1/2#

or

#x=49/22#----------------------------------Ans #2#