How do you solve the following system?: $-2y=2x+6 , -x-8y=32$

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Answer 1 · 2016-03-26T14:20:47

The solution for the system of equations is:
$color(blue)( x = 8/7$
$color(blue)(y = -29 / 7$

$-2y = 2x +6$
$color(blue)(2x) + 2y = -6$ ..........equation $(1)$

$-x -8y =32$ , multiplying by $2$
$color(blue)(-2x) -16y =64$ .....equation $(2)$

Solving by elimination:

Adding equations $1$ and $2$ :

$cancelcolor(blue)(2x) + 2y = -6$
$cancelcolor(blue)(-2x) -16y =64$

$-14y = 58$

$y = 58 / (-14)$

$color(blue)(y = -29 / 7$

Finding $x$ from equation $2$ :
$-x -8y =32$

$-8y - 32 = x$

$-8 * color(blue)(( 29 / (-7))) - 32 = x$

$232/7 - 32 = x$

$232/7 - 224/7 = x$

$color(blue)( x = 8/7$

The solution for the system of equations is:
$color(blue)( x = 8/7$
$color(blue)(y = -29 / 7$

How do you solve the following system?: -2y=2x+6 , -x-8y=32 -2y=2x+6 , -x-8y=32