Question

How do you solve the following system?: `3x-2y=4 , x-4y=3`

Answer 1

I found:
`x=1`
`y=-1/2`

Explanation:

We can isolate `x` from the second equation and substitute into the first to find `y`:
`x=4y+3`
Into the first:
`3(color(red)(4y+3))-2y=4`
`12y+9-2y=4`
`10y=-5`
`y=-5/10=-1/2`
Use this value back into:
`x=4(color(red)(-1/2))+3=-2+3=1`