# How do you solve the following system?:  3x-2y=4 , x-4y=3

Nov 19, 2015

I found:
$x = 1$
$y = - \frac{1}{2}$

#### Explanation:

We can isolate $x$ from the second equation and substitute into the first to find $y$:
$x = 4 y + 3$
Into the first:
$3 \left(\textcolor{red}{4 y + 3}\right) - 2 y = 4$
$12 y + 9 - 2 y = 4$
$10 y = - 5$
$y = - \frac{5}{10} = - \frac{1}{2}$
Use this value back into:
$x = 4 \left(\textcolor{red}{- \frac{1}{2}}\right) + 3 = - 2 + 3 = 1$