Question

How do you solve the following system: `3x + 4y = 11 , x-10y=10`?

Answer 1

Hence the solution is
`-=(x,y)=-=(4.41,-0.559`

Explanation:

`3x+4y=11`-----(1)
`x-10y=10`-----(2)
`x+1.333y=3.667`------(3)=(1)/3
`-11.333y=6.333`-----(4)=(2)-(3)
`y=-0.559`-------(5)=(4)/-11.333
Substituting in (2)
`x-10xx(-0.559)=10`
`x+5.590=10`
`x=10-5.59`
`x=4.41`
Check:
`3x+4y=3(4.41)+4(-0.559)=11`verified
`4.41-10(-0.559)=10`verified
Hence the solution is
`-=(x,y)=-=(4.41,-0.559`

Answer 2

`x = 75/17`, `y = -19/34`

Explanation:

(1) `3x+4y=11`
(2) `x-10y =10`

Solving (2) for x:
(3) `x = 10y+10`

Substituting (3) into (1):
`3(10y+10)+4y=11`

`30y+30+4y=11`

`34y=-19`

(4) `y = -19/34`

Substituting (4) into (2):
`x-10(-19/34)=10`

`x+95/17 = 170/17`

`x = 75/17`

(5) `x = 75/17`