How do you solve the following system?: $3x -9y =-13 , -2x +17y = 8$

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Answer 1 · 2016-04-29T22:47:47

$x=-139/69$
$y = 50/69$

$3x-9y = -13$ and
$-2x+17y = 8$

multiply first statement by "2" and the second statement by "3" to get to a common coefficient of 'x'
$2(3x-9y) = 2(-13)$
$3(2x+17y) = 3(8)$

$6x-18y = -26$
$6x+51y = 24$

then, subtract second statement from first statement
$-69y = -50$

now that y is isolated, we know that
$y = 50/69$

to solve for x, substitute the value for 'y' into one of the statements

$3x-9(50/69) = -13$

divide the statement by 3
$x-3(50/69)=-13/3$
$x-(50/23)=-13/3$
$x=-13/3 +50/23$

lastly, solve for lowest common denominator
$x=(-299 + 150)/69=-139/69$

How do you solve the following system?: 3x -9y =-13 , -2x +17y = 83x -9y =-13 , -2x +17y = 8