How do you solve the following system?: 3x-y=4 , 3x - 5y = 2 3xy=4,3x5y=2

1 Answer
May 18, 2018

Lettuce solve 3x3x

1^(st)" equation"1st equation

3x-y=43xy=4

Transfer yy

3x=4+y3x=4+y
Just remember this value as in the next equation we have 3x3x too

color(blue)(x=(4+y)/3x=4+y3

2^(nd)" equation"2nd equation

3x-5y=23x5y=2

Put value of 3x3x

4+y-5y=24+y5y=2

4-4y=244y=2

Factorize 44 outta it

4(1-y)=24(1y)=2

Transfer 44

1-y=2/41y=24

Transfer 1

-y=1/2-1y=121

Common Denominator

-y=1/2-2/2y=1222

cancel-y=cancel-1/2

color(Red)(y=1/2

x=(4+y)/3

You get

x=(4+1/2)/3

Common denominator

x=(8/2+1/2)/3

x=9/2 div 3

Invert

x=cancel9^3/2xx1/cancel3

You end up with

color(red)(x=3/2