Question

How do you solve the following system?: `3x-y=4 , 3x - 5y = 2`

Answer 1

Lettuce solve `3x`

`1^(st)" equation"`

`3x-y=4`

Transfer `y`

`3x=4+y`
Just remember this value as in the next equation we have `3x` too

`color(blue)(x=(4+y)/3`

`2^(nd)" equation"`

`3x-5y=2`

Put value of `3x`

`4+y-5y=2`

`4-4y=2`

Factorize `4` outta it

`4(1-y)=2`

Transfer `4`

`1-y=2/4`

Transfer 1

`-y=1/2-1`

Common Denominator

`-y=1/2-2/2`

`cancel-y=cancel-1/2`

`color(Red)(y=1/2`

`x=(4+y)/3`

You get

`x=(4+1/2)/3`

Common denominator

`x=(8/2+1/2)/3`

`x=9/2 div 3`

Invert

`x=cancel9^3/2xx1/cancel3`

You end up with

`color(red)(x=3/2`