# How do you solve the following system: 3x+y=8, -x+6y=12 ?

Mar 23, 2018

Arrange the equations

#### Explanation:

$3 x + y = 8$
$- 3 x + 18 y = 36$

After expanding the 2nd equation by 3. Sum these up:

$19 y = 44$

$y = \frac{44}{19}$

Put this value into the first original equation:

$3 x = 8 - \frac{44}{19}$

$3 x = \frac{152 - 44}{19}$

$3 x = \frac{108}{19}$

$x = \frac{108}{57}$

$x = \frac{36}{19}$