How do you solve the following system: #3x+y=8, -x+6y=12 #?

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Answer 1 · 2018-03-23T11:58:32

Arrange the equations

#3x + y = 8#
#-3x + 18y = 36#

After expanding the 2nd equation by 3. Sum these up:

#19 y = 44#

#y = 44/19#

Put this value into the first original equation:

#3x = 8 - 44/19#

#3x = (152-44)/19#

#3x = 108/19#

#x = 108/57#

#x =36/19#