# How do you solve the following system: 4x+3y=36, 4x + 2y = 10 ?

Feb 27, 2016

$\left(- 10.5 , 26\right)$

#### Explanation:

Given equations
$4 x + 3 y = 36$---------(1)
$4 x + 2 y = 10$---------(2)

Subtract equation 2 from equation 1

$y = 26$

Substitute in equation 1

$4 x + 3 y = 36$

$4 x + 3 \left(26\right) = 36$

$4 x + 3 \left(26\right) = 36$

$4 x + 78 = 36$

$4 x = 36 - 78$

$4 x = 36 - 78$

$4 x = - 42$

$x = - \frac{42}{4}$

$x = - 10.5$