How do you solve the following system: #4x+3y=36, 4x + 2y = 10 #?

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Answer 1 · 2016-02-27T07:39:01

#(-10.5,26)#

Given equations
#4x+3y=36#---------(1)
#4x+2y=10#---------(2)

Subtract equation 2 from equation 1

#y=26#

Substitute in equation 1

#4x+3y=36#

#4x+3(26)=36#

#4x+78=36#

#4x=36-78#

#4x=-42#

#x=-42/4#

#x=-10.5#