How do you solve the following system: #4x+3y= -7, y + 4x = 16 #?

1 Answer
Feb 14, 2016

Answer:

The solution for the system of equations is:
#color(blue)(x=55/8#

#color(blue)(y=-23/2#

Explanation:

#color(blue)(4x)+3y=-7#..........equation #1#

#color(blue)(4x)+y=16#.................equation #2#

Solving by elimination

Subtracting equation #2# from #1#
#cancelcolor(blue)(4x)+3y=-7#

#-cancelcolor(blue)(4x)-y=-16#

#2y=-23#

#color(blue)(y=-23/2#

Finding #x# from equation #1#

#4x+3y=-7#

#4x+3xx(-23/2)=-7#

#4x-69/2=-7#

#4x=-7 +69/2#

#4x=-14/2 +69/2#

#4x=55/2#

#x=55/(2xx4)#

#color(blue)(x=55/8#