How do you solve the following system: #4x-5y-23=0 , -2x=6y+18 #?

1 Answer
Mar 30, 2016

Answer:

#x = 1.41, y = -3.47#

Explanation:

For the first equation, start by adding #23# to both sides, so that:

#4x - 5y = 23#

Then for the second equation, subtract #6y# from both sides, so that:

#-2x - 6y = 18#

Then solve for #y# by multiplying the second equation by #2# on both sides and adding the two equations:

#4x - 5y = 23#
#+2*(-2x - 6y) = 2*18#

This gives:

#-17y = 59#, so #y = -3.47#

Then, to solve for #x#, multiply both sides of the first equation by 6 and both sides of the second equation by #-5 # and add them:

#6*(4x - 5y) = 6*23#
#+5*(2x - 6y) = -5*18#

This gives:

#34x = 48#, so #x = 1.41#

You can check your answers by substituting #1.41# for #x# and #-3.47# for #y#.