How do you solve the following system?: #4x-y=-1 , 6x - 4y = 3 #

1 Answer
May 25, 2018

Answer:

Use the elimination method.

Your answer is:
x = #-7/10#
y = #9/5#

Explanation:

I'd say for this one, I would use the elimination method. I'm not too good at formatting, but I'll give this my best shot.
Set it up like this:
4x - y = -1
6x - 4y= 3
Now, you want to get rid of one of the variables. Multiply (4x-y=-1) by -4. Now you have:
-16x + 4y = 4
6x - 4y = 3
Cancel out the 4y and -4y and add the rest of the similar terms. You're left with
-10x = 7
Divide both sides by -10 so you have just x.
x = #-7/10#

Now, plug x back into one of the equations. You can do either, but for this one I'll do the first one.
4( #-7/10#) - y = -1
4(#-7/10#)= #-28/10=-14/5#
So...
#-14/5# - y = -1
Move the #14/5# to the other side in order to isolate the y, by adding it.
-y = #-9/5#
Divide both sides by -1.
y = #9/5#

Your answer is:
x = #-7/10#
y = #9/5#