How do you solve the following system: 4x+y=-7, 2x + 3y = 8 ?

Apr 25, 2018

$\left(- 2.9 , 4.6\right)$

Explanation:

Rearrange the second equation to get:
$2 x = 8 - 3 y$

Also:
$2 \left(2 x\right) + y = - 7$
$2 \left(8 - 3 y\right) + y = - 7$
$16 - 6 y + y = - 7$
$- 5 y = - 23$
$y = \frac{23}{5} = 4.6$

Now we put this in:
$4 x + \frac{23}{5} = - 7$
$4 x = - 7 - \frac{23}{5} = \frac{- 35 - 23}{5} = - \frac{58}{5}$
$x = - \frac{58}{20} = - 2.9$

$\left(- 2.9 , 4.6\right)$