# How do you solve the following system: -5x + 3y= 6, 4x+3y=36 ?

$x = \frac{10}{3} \mathmr{and} y = \frac{68}{9}$
$- 5 x + 3 y = 6$ (1)
$4 x + 3 y = 36$ (2) Now subtracting (2) from(1) we get $- 9 x = - 30 \mathmr{and} x = \frac{30}{9} = \frac{10}{3}$Putting the value of x in equation (1) we get $3 y = 6 + 5 \cdot \frac{10}{3} \mathmr{and} y = \frac{68}{9}$[ans]