How do you solve the following system: $5 x - 7 y = 12, 2 x + 5 y = 2$ $5x - 7y = 12 , 2x + 5y= 2$ ?

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How do you solve the following system: $5 x - 7 y = 12, 2 x + 5 y = 2$ $5x - 7y = 12 , 2x + 5y= 2$ ?

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Answer 1 · 2015-12-06T13:53:33

$5 x - 7 y = 12$ $5x-7y=12$ (Consider this equation as equation 1)
$2 x + 5 y = 2$ $2x+5y=2$ (Consider this equation as equation 2)

$x = \frac{7 y + 12}{5}$ $x=(7y+12)/5$ (From equation 1)
Substitute this value of x in equation 2
$2 \frac{(7 y + 12)}{5} + 5 y = 2$ $2((7y+12))/5+5y=2$
$14 y + 24 + 25 y = 10$ $14y+24+25y=10$
$39 y = - 14$ $39y=-14$
$y = - \frac{14}{39}$ $y=-14/39$
Substitute this value of y in equation 1
$5 x - 7 (- \frac{14}{39}) = 12$ $5x-7(-14/39)=12$
$195 x + 98 = 468$ $195x+98=468$
$x = \frac{370}{195}$ $x=370/195$
$x = \frac{74}{39}$ $x=74/39$

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How do you solve the following system: $5 x - 7 y = 12, 2 x + 5 y = 2$ $5x - 7y = 12 , 2x + 5y= 2$ ?

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Science

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How do you solve the following system: 5x - 7y = 12 , 2x + 5y= 2 5x−7y=12,2x+5y=25x - 7y = 12 , 2x + 5y= 2 ?

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How do you solve the following system: $5 x - 7 y = 12, 2 x + 5 y = 2$ $5x - 7y = 12 , 2x + 5y= 2$ ?