How do you solve the following system?: $- 5 x - y = 1, 3 x - y = - 2$ $-5x -y =1, 3x -y = -2$

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Answer 1 · 2016-05-15T17:17:42

The solution for the set of equations is:

$x = - \frac{3}{8}$ $color(blue)(x = -3/8$

$y = \frac{7}{8}$ $color(blue)(y = 7/8$

$- 5 x - y = 1$ $-5x color(blue)(- y) = 1$ ...........equation $(1)$ $(1)$

$3 x - y = - 2$ $3x color(blue)(- y) = -2$ .........equation $(2)$ $(2)$

Subtracting equation $2$ $2$ from $1$ $1$ :

$-5x cancelcolor(blue)(- y) = 1$

$- 3x cancelcolor(blue)(+ y) = +2$

$-8x = 3$

$color(blue)(x = -3/8$

Finding $y$ from equation $1$

$-5x color(blue)(- y) = 1$

$-5x - 1 = y$

$-5 * color(blue)((-3/8)) - 1 = y$

$15/8- 1 = y$

$15/8- 8/8 = y$

$7/8 = y$

$color(blue)(y = 7/8$

How do you solve the following system?: -5x -y =1, 3x -y = -2−5x−y=1,3x−y=−2-5x -y =1, 3x -y = -2