# How do you solve the following system: 6x+2y=-4, 3x - 4y = -10?

Mar 24, 2016

$y = 1 , 6$
$y = - 6 , 8$

#### Explanation:

$6 x + 2 y = - 4 \text{ (1)}$
$3 x - 4 y = - 10 \text{ (2)}$
$\text{extend the equation (2) by 2}$
$6 x - 8 y = - 20 \text{ (3)}$
$\text{eliminate the equation (3) from (1) side by side}$
$\cancel{6 x} - \cancel{6 x} + 2 y + 8 y = - 4 + 20$
$10 y = 16$
$y = \frac{16}{10}$
$y = 1 , 6$
$\text{now use (1)}$
$6 \left(1 , 6\right) + 2 y = - 4$
$9 , 6 + 2 y = - 4$
$2 y = - 4 - 9 , 6$
$2 y = - 13 , 6$
$y = - \frac{13 , 6}{2}$
$y = - 6 , 8$