How do you solve the following system?: #6x - 4y = 3 , 5x - 2y = 1 #

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Answer 1 · 2015-12-02T11:14:59

#x=(-1)/4#
#y=(-9)/8#

#6x-4y=3# --------------(1)
#5x-2y=1# ------------------(2)
Let us have the equations as -

We are going to eliminate #y#

Before that understand #-4y +4y =0#

Multiply equation (2) with #-2#

#6x-4y=3# ------------------(1)
#-10x+4y=-2# ------------------(2)

Add (1) and (2), we get -

#-4x=1#
#x=(-1)/4#

Substitute #x=(-1)/4# in equation (1)

# 6((-1)/4)-4y=3#
# (-6)/4-4y=3#
# (-3)/2-4y=3#
#-4y = 3+3/2=(6+3)/2=9/2#
#y=9/2 xx1/(-4)=(-9)/8#