How do you solve the following system: #6x + y = 2, 2x + 3y = 34#?

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Answer 1 · 2018-03-25T00:08:18

#x=-7/4#
#y= 25/2#

Solve using substitution:
#6x+y=2#
#2x+3y= 34#

The first equation when solved for #y#:
#y=-6x+2#

Substitute for #y# into the second equation:
#2x+3(-6x+2)= 34#

Distribute:
#2x-18x+6= 34#

Combine like terms:
#-16x+6= 34#

Solve for x:
#-16x=28#
#x=28/-16#
#x=-7/4#

Solve for y by plugging in for #x#:
#y=-6(-7/4)+2#
#y= 42/4+2#
#y= 21/2+4/2#
#y= 25/2#