How do you solve the following system: $7 x - y = 10, 8 x - y = 13$ $7x - y = 10 , 8x - y = 13$ ?

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Answer 1 · 2016-01-06T08:36:17

$x = 3$ $x=3$ and $y = 11$ $y=11$

$7 x - y = 10$ $7x-y=10$ $.................(i)$
$8x-y=13$ $..................(ii)$

Subtract $(i)$ from $(ii)$
$implies x=3$

Put $x=3$ in $(i)$
$implies 7(3)-y=10$
$implies 21-y=10$
$implies y=11$
$implies y=11$

How do you solve the following system: 7x - y = 10 , 8x - y = 13 7x−y=10,8x−y=13 7x - y = 10 , 8x - y = 13 ?