How do you solve the following system: #8x-3y=3, 7x-2y= -67 #?

1 Answer

Answer:

We can use any of the 3 methods to solve it: Substitution, Elimination or Cross multiplication method.
I am using substitution method here to solve this system.

Explanation:

This is how we do this:
#8x-3y=3# (equa.1)
#x=(3+3y)/8#

#7x-2y=-67# (equa.2)
putting the value of 'x' in equation 2
#7*(3+3y)/8 -2y=-67#
#(21+21y)/8 -2y=-67#
#21+21y-16y=-67*8#
#21+5y=-536#
#5y=557#
#y=557/5#
now put the value of y in the equation 1 for getting the value of x.