# How do you solve the following system using substitution?: #3x=2y-5, y-5x=-1#

##### 1 Answer

#### Explanation:

Your system of equations looks like this

#{(3x = 2y - 5), (y - 5x = -1) :}#

The first thing to do here is rewrite the first equation to match the form of the second equation, i.e. get the

You can do that by adding

#3x - 2y = color(red)(cancel(color(black)(2y))) - color(red)(cancel(color(black)(2y))) = -5#

#3x - 2y = -5#

The system of equations now looks like this

#{(3x - 2y = -5), (-5x + y = -1) :}#

To solve this by using the *substitution method*, pick one of the two variables, solve one of the two equations for that variable, and use the resulting expression to find the other variable.

Simply put, let's say that you pick

#-5x + y = -1#

#color(red)(cancel(color(black)(5x))) - color(red)(cancel(color(black)(5x))) + y = -1 + 5x#

#y = 5x - 1" " " " color(red)("*")#

Now use this value of

#3x - 2 * overbrace((5x-1))^(color(blue)(=y)) = -5#

#3x - 10x + 2 = -5#

#-7x = -7 implies x = ((-7))/((-7)) = color(green)(1)#

Now that you know what the value of

#y = 5 * (1) - 1 = color(green)(4)#

The solution set for this system of equations is

#{(x=1), (y = 4) :}#