# How do you solve the following system using substitution?: 5x-2y=19, 3x+17y=34

Oct 27, 2015

$y = \frac{103}{97}$, x=?

#### Explanation:

Note that
$5 x - 2 y = 19$
$\implies x = \frac{2 y + 19}{5}$
Using the value of $x$ in $3 x + 17 y = 34$ we get
$\frac{3}{5} \cdot \left(2 y + 19\right) + 17 y = 34$
$\implies 6 y + 57 + 85 y = 170$
$\implies 91 y = 103$
$\implies y = \frac{103}{97}$
and put value of $y$ in $x = \frac{2 y + 19}{5}$ you will get $x$.