How do you solve the following system using substitution: $x + 3 y = - 3$ $x + 3y = -3$ and $9 y = - 3 x - 9$ $9y = -3x - 9$ ?

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How do you solve the following system using substitution: $x + 3 y = - 3$ $x + 3y = -3$ and $9 y = - 3 x - 9$ $9y = -3x - 9$ ?

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Answer 1 · 2015-03-29T18:33:12

There would be infinite number of solutions.

If we add 3x on both sides to the second equation, we would have 3x+9y=-3. Now, divide this equation by 3, we would have x+3y=-3. This equation is same as the first equation. We can now assign any number of values to x and we would have a distinct corresponding value of y. Thus there would be infinite number of solutions.

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How do you solve the following system using substitution: $x + 3 y = - 3$ $x + 3y = -3$ and $9 y = - 3 x - 9$ $9y = -3x - 9$ ?

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How do you solve the following system using substitution: x + 3y = -3x+3y=−3x + 3y = -3 and 9y = -3x - 99y=−3x−99y = -3x - 9?

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How do you solve the following system using substitution: $x + 3 y = - 3$ $x + 3y = -3$ and $9 y = - 3 x - 9$ $9y = -3x - 9$ ?