Question

How do you solve the following system using substitution?: `x=4-4y, -x+2y=2`

Answer 1

y = 1
x=0

Explanation:

First replace all values of x in the second equation with `4-4y` (this can be done for y as well but you would need to isolate the variable first)

Which gives you:
`-(4-4y)+2y=2`

Then solve using algebra:
Distribute the `-`
`-4+4y+2y=2`

Combine all all the y values
`-4+6y=2`

Add 4 to both sides
`(-4+6y)+4=(2)+4rarr6y=6`

Finally divide both sides by 6
`(6y)/6=6/6rarry=1`

Thus your y value is equal to 1. To find the x value, substitute this 1 into one of the equations for all y's
`x=4-4(1)`

Then simplify
`x=4-4rarrx=0`

thus x is equal to 0

You could also check your answer by substituting both values into the other equation
`-(0)+2(1)=2`

`0+2=2`

`2=2`

Your answers are correct!