How do you solve the following system: #x-2y=3, 2x+3y =4 #?

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Answer 1 · 2016-02-22T18:50:39

The solution for the system of equations is:

#x=17/7#
#y=-2/7#

#x-2y =3# , multiplying by #2#
#color(blue)(2x)-4y =6#.......equation #(1)#

#color(blue)(2x) +3y =4#........equation #(2)#

Solving by elimination:

subtracting equation #2# from #1#:

#cancelcolor(blue)(2x)-4y =6#

#-cancelcolor(blue)(2x) -3y =-4#

#-7y = 2#

#y=-2/7#

Finding #x# from equation #1#:
#x-2y =3#

#x=3+2y#

#x=3+2xx(-2/7)#

#x=3- 4/7#

#x=21/7- 4/7#

#x=17/7#