How do you solve the following system: #x+3y=2, 5x + 2y = 5 #?
2 Answers
By arranging the equation
Explanation:
Expand the first equation by
Now add this to the second equation:
Yielding:
Put this value in the first original equation:
Explanation:

You can use the "elimination" method to solve the equation system. To do this, you must destroy one of two variables (x, y). You have to equalize the coefficients in both equations by choosing one of the variables 'x' or 'y'.

x+3y=2
#" "# (1) ; 5x+2y=5#" "# (2) 
If both sides of equation (1) are multiplied by 5, the coefficients of 'x' are equal in both equations.

Now let's subtract equation (3) from equation (2).

5x+2y(5x+15y)=5(10)
#cancel(5x)+2ycancel(5x)15y=5+10#
#13y=15#
 Finally, in (1) or (2), write 15/13 instead of 'y'.