Question

How do you solve the following system?: `x + 3y = -3 , y=-x + 12`

Answer 1

`(39/2),(-15/2)`

Explanation:

`x + 3y=-3` and `y=-x+12`

we can substitute the value of y of the second equation in the first equation so we get,

`x + 3(-x+12) = -3`

On simplification

`x-3x+36=-3`

We get that `x=39/2`

Substituting it in either of the initial equations and solving for y, we get `y=-15/2`

So the solution to the given pair of equations is `x=39/2` and `y=-15/2`