Question

How do you solve the following system?: `x+3y=6, -x+y=-3`

Answer 1

I found:
`x=15/4`
`y=3/4`

Explanation:

I would try to add in columns the two equations:
`{(x+3y=6),(-x+y=-3):}`
`color(red)(0+4y=3`
so that `y=3/4`
substitute this value into the first equation:
`x+(3*color(blue)(3/4))=6`
`4x+9=24`
`x=15/4`