Question

How do you solve the following system: `x-4y=2, 3x-y=12`?

Answer 1

`x=46/11`
`y=6/11`-

Explanation:

`x-4y=2`
or
`3x-12y=6`
Subtracting the equation `3x-12y=6` from `3x-y=12`
we get
`3x-y-3x+12y=12-6`
or
`0+11y=6`
or
`11y=6`
or
`y=6/11`-----------------------Ans `1`
By putting the value `y=6/11` in the equation `x-4y=2`
we get
`x-4times6/11=2`
or
`x-24/11=2`
or
`x=2+24/11`
or
`x=46/11`------------------------------Ans `2`