# How do you solve the following system: x-4y=2, 3x-y=12 ?

Aug 10, 2016

$x = \frac{46}{11}$
$y = \frac{6}{11}$-

#### Explanation:

$x - 4 y = 2$
or
$3 x - 12 y = 6$
Subtracting the equation $3 x - 12 y = 6$ from $3 x - y = 12$
we get
$3 x - y - 3 x + 12 y = 12 - 6$
or
$0 + 11 y = 6$
or
$11 y = 6$
or
$y = \frac{6}{11}$-----------------------Ans $1$
By putting the value $y = \frac{6}{11}$ in the equation $x - 4 y = 2$
we get
$x - 4 \times \frac{6}{11} = 2$
or
$x - \frac{24}{11} = 2$
or
$x = 2 + \frac{24}{11}$
or
$x = \frac{46}{11}$------------------------------Ans $2$